YES Welcome to CiME version 2.02 - Built on 14/04/2004 13:29:51 - : unit = () - : unit = () X : variable_set = F : signature = R : HTRS = { __(__(X,Y),Z) -> __(X,__(Y,Z)), __(X,nil) -> X, __(nil,X) -> X, U11(tt) -> U12(tt), U12(tt) -> tt, isNePal(__(I,__(P,I))) -> U11(tt) } (6 rules) Termination now uses minimal decomposition - : unit = () Entering the termination expert for modules. Verbose level = 0 Checking module: {} The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: { U12(tt) -> tt } (1 rules) The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: { U11(tt) -> U12(tt) } (1 rules) The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: {} The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: { __(__(V_4,V_3),V_2) -> __(V_4,__(V_3,V_2)), __(V_4,nil) -> V_4, __(nil,V_4) -> V_4 } (3 rules) The dependency graph is (1 nodes) Checking each of the 1 strongly connected components : Checking component 1 Trying simple graph criterion. Trying to solve the following constraints: (5 termination constraints) Search parameters: linear polynomials, coefficient bound is 2. Solution found for these constraints: [nil] = 0; [__](X0,X1) = X1 + X0 + 1; ['__`](X0,X1) = X0; Checking module: { isNePal(__(V_0,__(V_1,V_0))) -> U11(tt) } (1 rules) The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Modular termination proof found. - : unit = () The module {} is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module { U12(tt) -> tt } (1 rules) is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module { U11(tt) -> U12(tt) } (1 rules) is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module {} is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module { __(__(V_4,V_3),V_2) -> __(V_4,__(V_3,V_2)), __(V_4,nil) -> V_4, __(nil,V_4) -> V_4 } (3 rules) is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has one strongly connected component: 0: '__`(__(V_4,V_3),V_2) ; '__`(V_3,V_2) 1: '__`(__(V_4,V_3),V_2) ; '__`(V_4,__(V_3,V_2)) 0 -> 0, 0 -> 1, 1 -> 0, 1 -> 1, On this component, the interpretation [nil] = 0; [__](X0,X1) = X1 + X0 + 1; ['__`](X0,X1) = X0; strictly decreases on every cycle The module { isNePal(__(V_0,__(V_1,V_0))) -> U11(tt) } (1 rules) is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. - : unit = () Quitting. Standard error: