YES Welcome to CiME version 2.02 - Built on 14/04/2004 13:29:51 - : unit = () - : unit = () X : variable_set = F : signature = R : HTRS = { U11(tt,M,N) -> U12(tt,M,N), U12(tt,M,N) -> s(plus(N,M)), plus(N,0) -> N, plus(N,s(M)) -> U11(tt,M,N) } (4 rules) Termination now uses minimal decomposition - : unit = () Entering the termination expert for modules. Verbose level = 0 Checking module: {} The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: {} The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: {} The dependency graph is (0 nodes) Checking each of the 0 strongly connected components : Checking module: { plus(V_1,s(V_0)) -> U11(tt,V_0,V_1), plus(V_1,0) -> V_1, U12(tt,V_0,V_1) -> s(plus(V_1,V_0)), U11(tt,V_0,V_1) -> U12(tt,V_0,V_1) } (4 rules) The dependency graph is (1 nodes) Checking each of the 1 strongly connected components : Checking component 1 Trying simple graph criterion. Trying to solve the following constraints: (7 termination constraints) Search parameters: linear polynomials, coefficient bound is 2. Solution found for these constraints: [tt] = 0; [s](X0) = X0 + 2; [0] = 0; [U11](X0,X1,X2) = X2 + X1 + 2; [U12](X0,X1,X2) = X2 + X1 + 2; [plus](X0,X1) = X1 + X0; ['U11`](X0,X1,X2) = 2*X1 + 2; ['U12`](X0,X1,X2) = 2*X1 + 1; ['plus`](X0,X1) = 2*X1; Modular termination proof found. - : unit = () The module {} is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module {} is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module {} is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has no strongly connected components. The module { plus(V_1,s(V_0)) -> U11(tt,V_0,V_1), plus(V_1,0) -> V_1, U12(tt,V_0,V_1) -> s(plus(V_1,V_0)), U11(tt,V_0,V_1) -> U12(tt,V_0,V_1) } (4 rules) is CE-terminating by criterion with marks except on AC-symbols, and with graph; the dependency graph has one strongly connected component: 0: 'U11`(tt,V_0,V_1) ; 'U12`(tt,V_0,V_1) 1: 'U12`(tt,V_0,V_1) ; 'plus`(V_1,V_0) 2: 'plus`(V_1,s(V_0)) ; 'U11`(tt,V_0,V_1) 0 -> 1, 1 -> 2, 2 -> 0, On this component, the interpretation [tt] = 0; [s](X0) = X0 + 2; [0] = 0; [U11](X0,X1,X2) = X2 + X1 + 2; [U12](X0,X1,X2) = X2 + X1 + 2; [plus](X0,X1) = X1 + X0; ['U11`](X0,X1,X2) = 2*X1 + 2; ['U12`](X0,X1,X2) = 2*X1 + 1; ['plus`](X0,X1) = 2*X1; strictly decreases on every cycle - : unit = () Quitting. Standard error: